(2x+5)(4x^2+20x+25)=0

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Solution for (2x+5)(4x^2+20x+25)=0 equation: 


Simplifying
(2x + 5)(4x2 + 20x + 25) = 0

Reorder the terms:
(5 + 2x)(4x2 + 20x + 25) = 0

Reorder the terms:
(5 + 2x)(25 + 20x + 4x2) = 0

Multiply (5 + 2x) * (25 + 20x + 4x2)
(5(25 + 20x + 4x2) + 2x * (25 + 20x + 4x2)) = 0
((25 * 5 + 20x * 5 + 4x2 * 5) + 2x * (25 + 20x + 4x2)) = 0
((125 + 100x + 20x2) + 2x * (25 + 20x + 4x2)) = 0
(125 + 100x + 20x2 + (25 * 2x + 20x * 2x + 4x2 * 2x)) = 0
(125 + 100x + 20x2 + (50x + 40x2 + 8x3)) = 0

Reorder the terms:
(125 + 100x + 50x + 20x2 + 40x2 + 8x3) = 0

Combine like terms: 100x + 50x = 150x
(125 + 150x + 20x2 + 40x2 + 8x3) = 0

Combine like terms: 20x2 + 40x2 = 60x2
(125 + 150x + 60x2 + 8x3) = 0

Solving
125 + 150x + 60x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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